bash double quotes inside backticks

Addition to the accepted answer: While I generally agree with @l0b0's answer here, I suspect the placement of bare backticks in the "worst to best" list is at least partly a result of the assumption that $(...) is available everywhere. Double Quotes. Putting \ in front of a metacharacter removes its special meaning. Backslash ( ) can also retain its value when it is used by following backticks, double quote and backslash. I was at first worried that `date '+%m'` would return a string but apparently expr does the math okay normally, so the problem is how to get it to evaluate an inner set of backticks within the outer set of backticks. Double quotes escape most characters, except the double quote " the backtick `, the dollar sign $, the backslash \, and the exclamation mark !. How can I tell it to evaluate an expression within another expression evaluation? Enclosing characters in double quotes (‘"’) preserves the literal value of all characters within the quotes, with the exception of ‘$’, ‘`’, ‘\’, and, when history expansion is enabled, ‘!When the shell is in POSIX mode (see Bash POSIX Mode), the ‘!’ has no special meaning within double quotes, even when history expansion is enabled. In the meantime, all my notes are in the attached text file. Single Quotes. Wrapping single quotes inside of double quotes will cancel out the expected behavior of the single quotes in the MySQL Query and instead treat it as part of the string. No character in the single quote has special meaning. Double quotes. In fact, with $() instead of backticks, you should be able to keep the inner double quotes: grep "$(date +"%b %d")" A double quote may be quoted within double quotes by preceding it with a backslash. Backticks within backticks? Single Quotes This works inside double quotes, or in the absence of quotes. After then, bash start parsing the command substitution. All characters within are interpreted as regular characters except for $ or ` which will be expanded on the shell. This allows us to use old-style command substitution with backticks and variable substitution (dollar sign) within double quoted strings: All behaviour being studied can be explained by the documentation except for escaping double quotes in an inner backticks string inside a double quoted string. Inserting two double quotes in the middle of the string will cancel out one of them. 3.1.2.3 Double Quotes. Double quotes ( ” ) is another way to preserve the literal value of the characters. This can be seen in columns 2 and 3 in the example above. And thus ends the lesson of the quotes. (There are slight differences between the shells on this.) Here is an example where backticks and $() behave differently: $ echo "$(echo \"test\")" "test" $ echo "`echo \"test\"`" test My understanding was this is because "backslashes (\) inside backticks are handled in a non-obvious manner" But it seems like this is something else because when I remove outer double quotes the results became similar: It does not work inside single quotes. The dollar sign ( $ ) and backticks ( ` ) characters can able to keep their special meaning within double quotes. All characters within single quotes are interpreted as a string character. First, bash parse the right hand side of assignment to one long string $( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd ) because double quote can appear inside double quotes. Bash escape quotes – Linux Hint, grep "$(date +'%b %d')". Use when you want to enclose variables or use shell expansion inside a string. 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