limiting reactant multiple choice questions

Q 4. /Type /XObject BT BT Q /BBox [0 0 9.507 2.074] Q 0 -0.003 l >> 45.287 0 0 45.783 463.732 245.416 cm /FormType 1 -0.002 Tc q q q /Meta94 Do 1.047 -0.003 l /FormType 1 BT q /BBox [0 0 9.507 1.795] q q /F1 6 0 R [(O)] TJ /F1 6 0 R Q stream /Resources << /Length 55 q /F1 6 0 R >> -0.007 Tc /Type /XObject /Type /XObject 0 g stream /Type /XObject endstream q 2.94 0.422 TD /Font << Q /BBox [0 0 9.507 1.795] 0 0.279 m 0 G /Type /XObject 0 0.279 m ET /FormType 1 /Subtype /Form Q >> q /Subtype /Form /Meta169 183 0 R stream Q q q 1.047 -0.003 l endstream 0 g endobj /Resources << endobj 0000012008 00000 n Multiple Choice (Choose the best answer.). 0 0.279 m 0 0.083 TD /Type /XObject /Length 71 endobj /BBox [0 0 0.263 0.279] /Type /XObject Q ET 45.663 0 0 45.783 179.922 245.416 cm /Length 64 Q /Meta226 Do /Length 122 Q endobj /Length 67 0 0.279 m 0.267 -0.003 l /Type /XObject 0000059966 00000 n In problem 8, which substance is the limiting reactant? 0.458 0 0 RG The lowest value is the LR and the highest value is the ER. Question: Multiple Choice: In The Reaction: C + 2Cl2 --> CCl4, Chlorine Is The A. Oxidizing Agent B. 0000051463 00000 n /Subtype /Form W* n Q W* n endstream /Meta14 Do q /Length 65 0 0.083 TD q >> q 45.289 0 0 45.355 81.303 493.844 cm /Resources << W* n 0 0.279 m 0.564 G /Meta17 28 0 R Q q /Matrix [1 0 0 1 0 0] /F1 0.217 Tf >> q q /Meta79 Do /Font << q ET 45.663 0 0 45.783 448.676 245.416 cm endobj endstream /FormType 1 /Type /XObject /F1 0.217 Tf q 0.458 0 0 RG /F1 0.217 Tf 133 0 obj << /Matrix [1 0 0 1 0 0] 0 G [(3)] TJ /Type /XObject /F1 0.217 Tf /FormType 1 q 135 0 obj << /Subtype /Form 203 0 obj << 0 G /Meta190 Do q 0.267 0.279 l endobj 6.051 0.087 TD 1.047 0.279 l 0000042599 00000 n stream /Length 54 [(O)] TJ endstream /F1 0.217 Tf W* n /FormType 1 • All questions are multiple choice. 45.663 0 0 45.783 269.506 365.866 cm Q Q 164 0 obj << 0 g /Resources << 0 w Q endobj Q q >> W* n Correct 2.7 g Al is 0.10 mole, 100 mL of 1 M HCl is 0.10 mole. /BBox [0 0 0.531 0.279] q 0.267 0.279 l 45.663 0 0 45.783 269.506 112.169 cm /FormType 1 /Meta144 Do 0.004 Tw /BBox [0 0 1.047 0.279] /Font << /Length 67 endobj /Matrix [1 0 0 1 0 0] 0.066 0.083 TD 45.289 0 0 45.355 81.303 493.844 cm 001 10.0points If a reaction of 5.0 g of hydrogen with 5.0 g of carbon monoxide produced 4.5 g of methanol the next column or page /Meta215 229 0 R BT >> /Matrix [1 0 0 1 0 0] Q /Subtype /Form stream q Q /Meta168 Do stream endstream q 0.001 Tw W* n /Resources << 0 1.46 m 1.047 -0.003 l 0 1.036 TD Q endstream ET 0 -0.003 l 0.564 G 0 G endstream Q /Meta113 127 0 R /BBox [0 0 1.047 0.279] 45.289 0 0 45.355 81.303 493.844 cm q 0 G /Matrix [1 0 0 1 0 0] ____ 1. /Matrix [1 0 0 1 0 0] /FormType 1 0.458 0 0 RG endstream /Matrix [1 0 0 1 0 0] BT /Meta75 Do q /Meta242 Do 0 g /Matrix [1 0 0 1 0 0] /BBox [0 0 1.047 0.279] /Type /XObject >> 0000025524 00000 n >> /BBox [0 0 9.507 2.074] BT /F3 0.217 Tf /Matrix [1 0 0 1 0 0] ET Q stream q 45.287 0 0 45.783 284.563 245.416 cm 0 g ET Q >> /Subtype /Form 0000000011 00000 n stream 1.047 -0.003 l q endobj /Descent -277 q /BBox [0 0 9.507 2.074] /Font << >> 45.287 0 0 45.783 194.978 245.416 cm /Meta127 Do Q /Length 55 /Font << [( \(aq\))] TJ ET 45.663 0 0 45.783 90.337 112.169 cm W* n 9.775 0.279 l 0 g 196 0 obj << /Meta158 172 0 R ET /BBox [0 0 1.047 0.279] /Length 55 /Type /XObject 0.267 0.279 l 0 g /Meta42 Do stream >> /Meta52 65 0 R /Matrix [1 0 0 1 0 0] /FormType 1 /Meta137 Do >> /BBox [0 0 9.507 2.074] 0 g /BBox [0 0 0.263 0.279] /F1 6 0 R Q /Type /XObject 255 0 obj << /F1 0.217 Tf [(B\))] TJ Q /FormType 1 Q q 0 -0.003 l endstream /Length 55 ET 0 -0.003 l 45.287 0 0 45.783 36.134 42.91 cm endobj 45.663 0 0 45.783 448.676 365.866 cm q /Length 122 q /Meta15 Do BT Q /Meta234 248 0 R /Resources << 0000004064 00000 n 578.159 655.699 l >> >> q q Q /Meta22 Do BT Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al + 3Cl2 - … stream /Type /XObject >> q 0.564 G 45.289 0 0 45.354 81.303 130.236 cm /F1 0.217 Tf endobj 0 0.279 m 0 g stream /Matrix [1 0 0 1 0 0] >> 0 g 0000088338 00000 n /Matrix [1 0 0 1 0 0] Q 100 0 obj << W* n endobj stream endobj /Meta162 176 0 R 121 0 obj << /DescendantFonts [<> The coefficients in a chemical equation represent the a. masses, in grams, of all reactants and products. 1.047 0.279 l /Meta102 116 0 R /Type /XObject 0 0.279 m Q 0.564 G Q q stream BT [(O)] TJ /BaseFont /LGVEOV+TestGen /FormType 1 q BT /BBox [0 0 9.507 1.562] ET 0.346 0.083 TD 0 G q /Meta59 Do /FormType 1 /Meta112 126 0 R q /FormType 1 0 0.279 m ET Q 182 0 obj << 0 -0.003 l /F1 0.217 Tf 0 w /Subtype /Form -0.001 Tw >> 0 0.279 m Q Q q /F1 6 0 R 0 G >> q endobj >> -0.002 Tc /Subtype /Form q Worked example: Calculating the amount of product formed from a limiting reactant. Q For the balanced equation shown below, if 93.8 grams of PCl5 were reacted with 20.3 grams of … endobj >> /Flags 32 0.267 -0.003 l ET /Subtype /Form 31 0 obj << /Type /XObject 0 G 0 0.279 m /Font << [( of)] TJ 0 0.279 m /Type /Font -0.001 Tc q /Meta100 Do /Type /XObject Q 0 g 0.564 G 45.663 0 0 45.783 90.337 475.777 cm Q 134 0 obj << W* n q 0.267 -0.003 l /FormType 1 Introduction to gravimetric analysis: Volatilization gravimetry. 0 0.279 m ET /Matrix [1 0 0 1 0 0] 1.047 -0.003 l /F1 0.217 Tf /Subtype /Form /Length 56 -0.003 Tc 68 0 obj << >> /F1 0.217 Tf /Meta6 14 0 R 1 g 0.267 0.279 l 0000031721 00000 n 0 0.279 m endobj stream >> /Meta232 246 0 R Q /Length 67 stream 0000012814 00000 n You will then need to correctly identify the limiting reactant. -0.001 Tw /Type /XObject >> endstream /Matrix [1 0 0 1 0 0] ET 0000034942 00000 n ET /Meta247 Do /Length 122 endobj /Length 161 /Resources << /Subtype /Form 1.047 -0.003 l q 0.267 0.279 l >> /BBox [0 0 1.047 0.279] /Length 55 Q 0.015 w 0.564 G /Subtype /Form /FormType 1 256 0 obj << /Subtype /Form stream >> Q 0 g /BBox [0 0 1.047 0.279] q Q /Resources << /FormType 1 1 j W* n /Matrix [1 0 0 1 0 0] Q endobj Find the number of moles available for each reactant. /Meta194 Do Q 0.267 0.279 l 0000050227 00000 n endstream Q q endobj [(3)] TJ 1 g ET Q Q endstream /Length 73 >> /Resources << >> Q endobj /BBox [0 0 0.531 0.279] q endobj -0.001 Tc /FormType 1 0.015 w Q endstream /Font << 0000023446 00000 n /Subtype /Form 0000032469 00000 n q q q BT /Height 17 This quiz and corresponding worksheet will help you gauge your understanding of calculating reaction yield and percentage yield from a limiting reactant. 0 w >> 0000056339 00000 n 45.289 0 0 45.354 81.303 130.236 cm >> /Meta159 Do 0.814 1.032 TD ET /FormType 1 q /Meta212 Do Q endstream /Matrix [1 0 0 1 0 0] /Meta237 251 0 R /BBox [0 0 9.507 2.074] >> 0 w Q -0.012 Tc 1.047 0.279 l ET 0 g Q Q /Meta51 Do 0 g 0.267 -0.003 l [(3)] TJ endstream 1.811 0.422 TD 0.564 G BT The %)] TJ /F1 0.217 Tf 0000055090 00000 n 0000006145 00000 n /Meta66 80 0 R 45.287 0 0 45.783 463.732 475.777 cm You probably used Al as the limiting reagent. /Resources << Q 0000001748 00000 n 0.015 w (c) has the smallest coefficient. /FormType 1 0 g 62 0 obj << W* n >> 0000065065 00000 n /FormType 1 >> endstream /Length 187 /Subtype /Form =*endstream q 1.047 0.279 l /Subtype /Form BT ET Q /F1 6 0 R >> Q 55 0 obj << Q W* n /FormType 1 [(\()-25(O)-25(H\))] TJ endobj /Font << Q 0.458 0 0 RG q /Matrix [1 0 0 1 0 0] 0000041583 00000 n q /FormType 1 endobj Q Q xÚûãÿ/7O7FFF dø›ÁÈ£ü?ÀÀÍÁ ÈäÃÈ(Èğÿƒ021³°²±sprql``bdffbafeeaÊÖåXY… لٕ 45.324 0 0 45.783 54.202 331.99 cm 45.663 0 0 45.783 359.091 365.866 cm 0 g 9.775 -0.003 l 0.458 0 0 RG Q /Matrix [1 0 0 1 0 0] 0.047 0.083 TD /Type /XObject /BBox [0 0 9.507 1.46] Q ET /Matrix [1 0 0 1 0 0] q BT q /Subtype /Form >> Q /Font << q /F1 6 0 R /Length 67 >> Q q 0000017328 00000 n 6.165 0.138 TD Q /Encoding /WinAnsiEncoding 0.314 0.279 l >> endstream /Meta194 208 0 R /BBox [0 0 1.047 0.279] q q BT /Subtype /Form >> ET 94 0 obj << /Length 63 q Q /Type /Page 9.775 0.279 l /F1 0.217 Tf BT [( Al\(N)] TJ stream q /F1 6 0 R q /Type /XObject /Meta242 256 0 R /F1 6 0 R endstream /FormType 1 /Length 122 q /FormType 1 >> /FormType 1 startxref 199 0 obj << 0.001 Tc Q /Type /XObject 11.968 0.279 l Q /F1 0.217 Tf stream Q /Type /XObject /BBox [0 0 1.047 0.279] endstream 162 0 obj << /F3 0.217 Tf /Resources << /Meta48 Do 2.527 0.752 TD 1.047 0.279 l q BT 39 0 obj << /FormType 1 q BT 45.289 0 0 45.313 81.303 599.238 cm [(p)-15(ol)21(lutan)16(t:)] TJ W* n >> 0.005 Tw Q 0.066 0.083 TD [(B\))] TJ endstream q >> 227 0 obj << endobj Q q /Subtype /Form W* n /Meta24 37 0 R [(O)] TJ /Meta225 239 0 R /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] ET >> /FormType 1 0.015 w /Length 54 [(S)-18(u)22(lfur and )23(oxy)21(gen re)20(act in a )18(combin)15(ation r)23(eactio)28(n to prod)25(uce )16(sulfur t)32(rioxide, )19(an en)16(vir)17(o)-15(n)20(men)21(t)-18(al)] TJ stream q q 0 g /BBox [0 0 0.263 0.279] /Resources << endstream endstream 0000005913 00000 n endstream /Meta192 206 0 R q 45.289 0 0 45.355 81.303 493.844 cm A) the product of a reaction B) is a reactant C) one of the reactants in single-replacement reactions D) a solid product of a reaction E) a chemical that speeds up the reaction 21) When the following equation is balanced, KClO 3 (s) KCl(s) + O 2 0000066581 00000 n /BBox [0 0 9.507 1.795] /Meta128 Do stream /F1 6 0 R Q 1.047 -0.003 l 0 G In an experiment, 3.25 g of NH 3 are allowed to react with 3.50 g of O 2. 0 0.279 m /FormType 1 /Length 124 /Type /XObject 0000053312 00000 n Q q q /Type /XObject /F1 0.217 Tf /Type /XObject 0.267 -0.003 l Q 0.015 w /BBox [0 0 9.507 2.074] endstream >> Q /Meta143 Do /Length 66 /F1 0.217 Tf 0 g 0.564 G stream Q /Font << >> [(Al)] TJ /F1 0.217 Tf /Meta5 13 0 R /Meta123 Do /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /StemH 88 /FormType 1 /Type /XObject 0000024431 00000 n /Font << Hint. /Meta169 Do endobj [( 3AgC)-23(l \(s)-22(\))] TJ 538.26 655.699 m 0000044218 00000 n q 45.287 0 0 45.783 374.147 475.777 cm q endobj 0 G W* n 0 g Q /FormType 1 0 G /Meta81 95 0 R q [(O)] TJ /Resources << >> Q 1.047 0.279 l 0 -0.003 l >> 1.047 -0.003 l 0 w Q >> >> /Resources << 45.289 0 0 45.313 81.303 599.238 cm /FormType 1 0000060710 00000 n >> 45.289 0 0 45.355 81.303 493.844 cm [( A)-14(l)] TJ /FontBBox [-90 -216 1195 800] BT /Matrix [1 0 0 1 0 0] [( \(g\))] TJ 0 w Q 0.015 w 45.324 0 0 45.783 54.202 441.9 cm /BBox [0 0 1.047 0.279] /Font << q 0.031 0.083 TD 9.775 -0.003 l -0.007 Tc xref q /I0 Do stream /Font << /FormType 1 /Subtype /Form /BBox [0 0 0.263 0.279] Q /Meta90 Do [(5\))] TJ /Matrix [1 0 0 1 0 0] 0.799 0.422 TD /BBox [0 0 0.314 0.279] 153 0 obj << 0000054583 00000 n 45.663 0 0 45.783 269.506 581.171 cm 77 0 obj << 0 g /Type /XObject stream /Leading 253 endobj >> >> 0000022511 00000 n 9.775 0 0 0.283 0 -0.003 cm 45.289 0 0 45.354 81.303 130.236 cm Q /Meta105 119 0 R endstream 0 0.083 TD 1.047 0.279 l /BBox [0 0 1.047 0.279] 45.663 0 0 45.783 448.676 581.171 cm q q /FormType 1 >> /Length 122 Q 249 0 obj << 0 G /Meta232 Do Q /Matrix [1 0 0 1 0 0] Q >> 0.458 0 0 RG 0.047 0.083 TD /FormType 1 0 -0.003 l 0 g /Type /XObject q 0 w 1.511 0.418 TD 0 g /Subtype /Form /Matrix [1 0 0 1 0 0] >> 218 0 obj << /Length 122 BT 45.289 0 0 45.287 81.303 263.484 cm 0 -0.003 l 0 g /FormType 1 q 0.458 0 0 RG /Type /XObject /Meta98 Do >> /FormType 1 1 g 0 g 0 0.083 TD 29 0 obj << >> 0000052810 00000 n q /Type /XObject Q 0000026272 00000 n /BBox [0 0 1.047 0.279] Q >> /Font << >> 0000068092 00000 n /Type /XObject /Resources << >> Q ET >> /BBox [0 0 1.047 0.279] Q /Matrix [1 0 0 1 0 0] q /Subtype /Form /Matrix [1 0 0 1 0 0] ET Q endobj ET /Meta208 Do Q q stream /Type /XObject /Resources << /Matrix [1 0 0 1 0 0] >> /BBox [0 0 0.263 0.279] Q /F1 6 0 R ET /BBox [0 0 9.507 1.562] endstream q /FormType 1 ET >> Stoichiometry and Limiting Reactant Quiz Version A (PLEASE DO NOT WRITE ON THE QUIZ) Multiple Choice Identify the choice that best completes the statement or answers the question. 45.289 0 0 45.313 81.303 599.238 cm /Subtype /Form >> 0.015 w q /BBox [0 0 9.507 2.074] W* n Q q Q q /Subtype /Form 0 0.279 m >> >> q 0 0.083 TD q 0000055592 00000 n /Resources << /Meta241 255 0 R 0.031 0.083 TD BT /BBox [0 0 0.263 0.279] /Meta110 124 0 R 0 g Q [<000F>] TJ /BBox [0 0 9.507 1.511] stream 0000033663 00000 n q /FormType 1 59 0 obj << /Type /XObject /Length 55 /Font << 0 0.279 m /Meta197 211 0 R 0000057108 00000 n 0 g Q /F1 0.217 Tf stream >> endobj stream q 192 0 obj << /Resources << 0 0.279 m /Subtype /Form 1 g endobj /Subtype /Form 0 g >> 167 0 obj << 1.047 0.279 l /Meta34 47 0 R endobj /Length 90 BT /Length 69 0 w Q /F1 6 0 R Q 1.047 0.279 l stream 0.458 0 0 RG Q >> 0 w /BBox [0 0 9.507 1.795] Q 0 g 0.015 w 0 264 0000050763 00000 n q /Meta83 97 0 R 0 w 38 0 obj << >> q Q 211 0 obj << 0 w endobj 0000005658 00000 n /F3 0.217 Tf Q >> 40 0 obj << /Font << -0.007 Tc endstream ET /FormType 1 0.531 -0.003 l /Meta70 Do stream /Meta241 Do 1 g /Matrix [1 0 0 1 0 0] >> >> q /BBox [0 0 1.047 0.279] 53 0 obj << [(In a particu)26(l)-16(ar )16(ex)15(p)-15(er)21(ime)20(nt, the rea)19(ction of )21(1.0 g S with 1. (d) is consumed completely. endobj stream BT stream /Length 722 0 G Q /Meta160 174 0 R /Meta222 Do /Font << Q stream q 0 -0.003 l q Q /Subtype /Form /Matrix [1 0 0 1 0 0] 45.287 0 0 45.273 36.134 694.845 cm BT 0 w /Meta6 Do 4.137 0.752 TD /Meta103 117 0 R BT endobj /Meta61 Do 0 -0.003 l Q stream BT /Subtype /Form /BBox [0 0 9.507 1.46] 0.001 Tc >> /Resources << /Matrix [1 0 0 1 0 0] /F1 6 0 R /Meta30 43 0 R Q /Font << 0 -0.003 l q >> /Type /XObject q >> /F1 0.217 Tf /Matrix [1 0 0 1 0 0] 215 0 obj << /Meta17 Do Q 0.066 0.083 TD stream /BBox [0 0 9.507 1.511] ET /Font << >> /Resources << 0 G /Matrix [1 0 0 1 0 0] endstream 45.289 0 0 45.274 81.303 383.934 cm Q /Type /XObject /BBox [0 0 0.263 0.279] 1 g /FormType 1 -0.007 Tc >> /BBox [0 0 9.507 2.074] >> /Length 122 BT /Type /XObject 165 0 obj << 0 -0.003 l ET 0.531 0.279 l 0000040570 00000 n /Font << 0.267 0.279 l 45.663 0 0 45.783 179.922 365.866 cm endstream q stream /FormType 1 0 g /Font << q /F1 6 0 R /Font << Evaporation. endstream endobj q >> >> >> /Resources << >> stream 0 0.279 m 0 G /BBox [0 0 9.507 1.795] endobj -0.001 Tw /Meta144 158 0 R 231 0 obj << /Meta40 Do [(3)51(.8)] TJ >> /Meta95 109 0 R W* n /Type /XObject Q 0 g 1.047 0.279 l [(E\))] TJ /Length 55 45.663 0 0 45.783 269.506 365.866 cm Multiple choice question. ET /Subtype /Form 11.968 -0.003 l /Matrix [1 0 0 1 0 0] 0000049156 00000 n /Length 76 1 J /Resources << 45.663 0 0 45.783 448.676 112.169 cm endstream 1 g /Type /XObject BT q 0 g /Meta119 133 0 R /F1 6 0 R 0000015815 00000 n 0 0.083 TD q /FormType 1 250 0 obj << Thus, HCl is the limiting reagent. 0 -0.003 l ET endobj /FormType 1 0 0 l 45.289 0 0 45.355 81.303 493.844 cm ET /BBox [0 0 1.047 0.279] stream BT 0 g 0 0.279 m endstream 45.289 0 0 45.313 81.303 599.238 cm Q /Resources << BT q Q ET /F1 0.217 Tf /Resources << Q 0 g 8.645 0.138 TD 0 0.279 m /FormType 1 endobj -0.007 Tc q /Meta225 Do q BT W* n /Meta106 Do [(Cl)] TJ Q W* n 0 -0.003 l q q /Font << /F1 0.217 Tf 116 0 obj << 0.015 w endstream Q /Meta173 Do Q /Subtype /Form 0 0.279 m BT 0.314 0.279 l /Meta145 159 0 R Q endobj /Subtype /Form /FormType 1 Q /I0 70 0 R /Resources << q 0.267 -0.003 l /Meta23 36 0 R Q >> endobj q 0.001 Tc /Font << ET 0.267 0.279 l W* n Q 1.527 0.422 TD 45.287 0 0 45.783 194.978 475.777 cm /Font << -0.001 Tc endobj /Subtype /Form endstream Q >> 0000000629 00000 n >> stream atoms/molecules/formula units) Chemical formulas or names: Formulas only Names only Mix & match formulas & names Display quiz as: 0.458 0 0 RG [(O)] TJ 0 -0.003 l /Length 81 q 0 G q >> /Type /XObject /Type /XObject q 45.324 0 0 45.783 54.202 331.99 cm /Matrix [1 0 0 1 0 0] /Font << 1 g /FormType 1 -0.007 Tc >> ET >> Q 0000058461 00000 n /BBox [0 0 9.507 1.511] /BBox [0 0 9.507 1.46] q 0 0.279 m >> 0000028819 00000 n /F1 0.217 Tf Q 0000015310 00000 n 2.791 1.036 TD /BBox [0 0 9.507 1.562] Q q /Meta173 187 0 R endobj /Resources << /Meta88 Do stream endstream 0 G /Font << stream /Font << /Size 264 /Matrix [1 0 0 1 0 0] Q 65 0 obj << q q q /Font << 0 w 0 0.279 m [(D\))] TJ 0000015554 00000 n endstream /Subtype /Form 0000009258 00000 n /F1 0.217 Tf Q q /Resources << 64 0 obj << >> >> /Resources << /Subtype /Form endobj q Q 0 0.279 m /Subtype /Form /Meta72 Do stream Q 45.289 0 0 45.354 81.303 130.236 cm S W* n /BBox [0 0 1.047 0.279] 0.267 0.279 l /Meta108 122 0 R /Subtype /Form /Length 66 /F1 6 0 R >> Q q /Subtype /Form 0 0.279 m 0 -0.003 l >> /Meta85 99 0 R /BBox [0 0 0.314 0.279] q 0.031 0.083 TD stream 0 g /BBox [0 0 9.507 1.511] 45.289 0 0 45.287 81.303 263.484 cm Q endobj 0.015 w stream Q -0.007 Tc /FormType 1 0000042352 00000 n /Length 279 0.001 Tc /Subtype /Form 9.507 -0.003 l >> BT q >> Q /Length 74 -0.002 Tw /Matrix [1 0 0 1 0 0] Q q >> 207 0 obj << /Length 55 /Meta233 Do endstream /F1 6 0 R Q q 0000053574 00000 n /Meta164 178 0 R Q 0000016560 00000 n 0 G 0 g /Meta170 184 0 R q Q >> /FormType 1 0 -0.003 l >> Q /Meta226 240 0 R [(?)] Q q q ET q 0 -0.003 l /BBox [0 0 11.968 0.279] 45.289 0 0 45.354 81.303 130.236 cm 0.015 w 4.503 0.418 TD /Length 122 q >> endobj >> /Matrix [1 0 0 1 0 0] Q W* n 80 0 obj << [(O)] TJ /Length 122 0 0.279 m 0 g stream Q 0 -0.003 l /FormType 1 /BBox [0 0 9.507 1.511] 1.047 -0.003 l /BBox [0 0 9.507 1.46] /Resources << /Subtype /Form Q 0 0.279 m stream 7. c. 3. b. >> /Font << 1 g >> /Matrix [1 0 0 1 0 0] /Meta219 Do stream 1.047 0.279 l >> /Meta60 Do q 1.047 0.279 l /Type /XObject 0 G ET /Matrix [1 0 0 1 0 0] q /F1 6 0 R 1 g /FormType 1 Q /Resources << /BBox [0 0 0.263 0.279] /Meta18 29 0 R /Length 155 /BBox [0 0 9.507 1.562] /Meta246 260 0 R /Type /XObject 219 0 obj << /Length 55 endstream >> q /Meta212 226 0 R /F1 6 0 R /FormType 1 /F1 0.217 Tf /Font << /Length 55 >> stream 155 0 obj << 24 0 obj << /Matrix [1 0 0 1 0 0] endstream /Matrix [1 0 0 1 0 0] 0 G /F1 6 0 R 0 g q q 0 w /FormType 1 When the formula equation is correctly balanced the coefficient of Fe is number a. /F1 6 0 R /Type /XObject 143 0 obj << /Meta161 175 0 R 0.267 0.279 l 0 w /Meta91 Do q BT Q q >> /Meta122 Do 34 0 obj << -0.002 Tc Q /F1 6 0 R /F1 0.217 Tf 0.531 0.279 l /Length 67 /Matrix [1 0 0 1 0 0] 0 0.083 TD /Type /XObject /ItalicAngle 0 0000008064 00000 n Q 0 -0.003 l /Subtype /Form q >> >> 45.289 0 0 45.354 81.303 130.236 cm >> /Length 58 /Type /XObject 0.458 0 0 RG Q 0.267 -0.003 l /Matrix [1 0 0 1 0 0] 0 w W* n /Resources << 0.015 w q 0.267 -0.003 l /Meta231 Do 45.289 0 0 45.355 81.303 493.844 cm /Length 67 q /F1 6 0 R Which substance is the limiting reactant when 8.0 g of sulfur reacts with 12 g of oxygen and 16 g of sodium hydroxide according to the following chemical equation: 2 S(s)+ 3 O 2 (g)+ 4 NaOH(aq)→ 2 Na 2 SO 4 (aq)+ 2 H 2 O(l) A) S(s) B) O 2 (g) C) NaOH(aq) D) None of these substances is the limiting reactant. endstream q 225 0 obj << ET endobj /BBox [0 0 0.263 0.279] q /Subtype /Form Q stream >> /Subtype /Form Q BT /Length 122 W* n 0 G /Font << 45.663 0 0 45.783 90.337 581.171 cm >> >> q /FormType 1 /FormType 1 q /Meta141 Do /Font << /Subtype /Form /Subtype /Form Q 0000070110 00000 n q /Length 55 [(2S \(s\))] TJ endobj The equation requires 3 moles of HCl for every mole of Al. 0 g 0 w 0 w 0 w /BBox [0 0 9.771 0.279] 45.663 0 0 45.783 179.922 475.777 cm 1.047 0.279 l q >> 0 g q /BBox [0 0 9.507 1.795] BT stream /Meta147 Do q /FormType 1 0 g 0 0.279 m /Type /XObject q Q Q 0 G /BBox [0 0 0.263 0.279] /Resources << Q 0000001095 00000 n /Subtype /Form q q /Type /XObject 0 g Q /F1 6 0 R 0 g /Meta175 Do 0 0.083 TD endobj /Length 122 [( M)27(g)] TJ 0000040832 00000 n Q endstream /Type /XObject 0000018079 00000 n 0000014548 00000 n /F1 6 0 R 0000037549 00000 n 0.015 w 0000061678 00000 n /FormType 1 -0.002 Tc /Subtype /Form ET >> 45.289 0 0 45.355 81.303 493.844 cm /F1 6 0 R [(3)] TJ /Meta45 Do /Meta10 Do 161 0 obj << 0.015 w endobj /F3 25 0 R /Matrix [1 0 0 1 0 0] /Type /XObject 0.814 1.036 TD ET ET ET /Length 67 0.314 0.279 l Q 0 0.083 TD q W* n 0.531 -0.003 l /Type /XObject /BBox [0 0 0.263 0.279] Q /Meta85 Do 0000041077 00000 n /Subtype /Form /Font << /Meta177 191 0 R endobj /F1 0.217 Tf /F1 0.217 Tf endstream 45.324 0 0 45.783 54.202 441.9 cm S /BBox [0 0 1.047 0.279] Q Q q q q W* n /F1 6 0 R q /Subtype /Form /Matrix [1 0 0 1 0 0] /FormType 1 endobj /Subtype /Form 0 g /Resources << 0 g /F1 6 0 R q /Length 54 /FormType 1 /Type /XObject endstream /F1 0.217 Tf /BBox [0 0 1.047 0.279] /FormType 1 /Resources << /FormType 1 endobj q 0.564 G /Subtype /Form 0 g 5.917 0.083 TD /Subtype /Form 45.287 0 0 45.783 105.393 581.171 cm q Q For each of the following questions or statements, select the most appropriate response and click its letter: Start Congratulations - you have completed Quiz #2-6 PRACTICE: Stoichiometry & Limiting Reagents . W* n /Length 121 q 237 0 obj << 0 0.279 m 0 g Q >> Q Q 1.047 -0.003 l q 0.564 G /Meta34 Do 0000036821 00000 n /Matrix [1 0 0 1 0 0] q /Meta56 Do 0 G /Type /XObject /FormType 1 stream 0 0.279 m q endstream Q >> /Type /XObject ET BT /Type /XObject /Resources << stream [( 2)16(S)] TJ stream /Subtype /Form 0 G q /F1 0.217 Tf /Meta186 200 0 R Q stream q 0 -0.003 l /Meta104 118 0 R q ET q BT 2.574 1.032 TD >> /FormType 1 /Meta245 259 0 R 45.287 0 0 45.783 463.732 112.169 cm [(0)-16(.0)-29(485)] TJ 45.289 0 0 45.287 81.303 263.484 cm /Font << /BBox [0 0 0.314 0.279] 117 0 obj << q 0.267 -0.003 l ET 0.267 0.279 l BT /F3 0.217 Tf 45.663 0 0 45.783 90.337 245.416 cm BT 45.287 0 0 45.783 105.393 112.169 cm 1 g q q 1.047 0.279 l /Matrix [1 0 0 1 0 0] 0000003058 00000 n Q stream endstream /Type /XObject 0000050997 00000 n ET /Type /XObject /Type /XObject /Subtype /Form q 118 0 obj << BT 0 g /BBox [0 0 9.507 1.795] /BBox [0 0 11.968 0.279] /Matrix [1 0 0 1 0 0] q 9.775 0.279 l Q >> ET /Subtype /Form Q /Subtype /Form q 0.267 -0.003 l /F4 0.217 Tf 0 -0.003 l /Length 122 stream endstream 45.289 0 0 45.354 81.303 130.236 cm /BBox [0 0 0.263 0.279] /Resources << /Resources << BT W* n /Font << >> /BBox [0 0 1.047 0.279] /Font << /Meta74 Do Stoichiometry and empirical formulae. 1.047 0.279 l >> /FormType 1 Q endstream /Meta76 Do 0 -0.003 l q Q Q /Font << endstream /Length 56 Pretend you have a job building tricycles. Q 0000020150 00000 n q Q /Matrix [1 0 0 1 0 0] Q Q TJ /Meta200 Do 254 0 obj << 3.555 0.752 TD 0.314 -0.003 l /Meta184 198 0 R >> Q >> /Subtype /Form >> endstream Q /Meta95 Do Q >> q /Meta166 Do /Font << /I0 70 0 R This quiz will cover some basic limiting reactant problems. /Meta116 130 0 R 0000028050 00000 n stream q 0.015 w 0000049651 00000 n 45.289 0 0 45.313 81.303 599.238 cm >> /F1 6 0 R /Meta185 199 0 R -0.007 Tc /BBox [0 0 1.047 0.279] /Meta222 236 0 R >> >> q BT >> q q 0000038544 00000 n /Type /XObject 83 0 obj << q /Meta114 Do 1.047 -0.003 l >> 0 0.279 m /Matrix [1 0 0 1 0 0] stream q 45.663 0 0 45.783 359.091 112.169 cm /Type /XObject q 1.996 1.032 TD >> q 45.287 0 0 45.783 105.393 475.777 cm 0.458 0 0 RG 1.047 0.279 l 0 0.279 m 45.287 0 0 45.783 374.147 112.169 cm BT >> /F1 6 0 R endstream endobj 0 G q BT q q >> q 1.047 0.279 l /Type /XObject stream 0000029333 00000 n q Q >> 0 g /Meta47 60 0 R q /Meta234 Do /Type /XObject q 45.289 0 0 45.287 81.303 263.484 cm /Font << /Meta163 177 0 R /Meta87 101 0 R q /F1 0.217 Tf /Matrix [1 0 0 1 0 0] /F1 6 0 R 0 -0.003 l Q /MaxWidth 1248 q /Type /XObject /Matrix [1 0 0 1 0 0] q Q endobj /Length 78 0 g /Type /XObject 0.031 0.083 TD stream stream 119 0 obj << /Resources << W* n 0 0.279 m Q Q 0000047008 00000 n >> >> /Meta91 105 0 R Q Q q 0000065834 00000 n /F1 6 0 R W* n Q /Meta120 Do /F1 6 0 R /Meta3 9 0 R q How many moles of what reactant is left over? /AvgWidth 657 ET 0 1.562 m 0000011025 00000 n q >> W* n /F1 6 0 R 0000010792 00000 n /FormType 1 222 0 obj << Q /Matrix [1 0 0 1 0 0] 0 g /Length 67 /Length 169 0 -0.003 l /FormType 1 /Type /XObject 187 0 obj << /F1 6 0 R /Length 122 0.015 w q /FormType 1 q q >> >> endobj 0.267 -0.003 l 45.663 0 0 45.783 359.091 475.777 cm 0 g /FormType 1 /Length 55 /Meta68 82 0 R 0000007901 00000 n 0.003 Tw Q /Meta1 Do /F1 0.217 Tf >> /Meta52 Do 0 g Q /Type /XObject /BBox [0 0 9.507 1.562] >> /Meta20 Do 1.047 0.279 l q 0.267 0.279 l Q Q q 0 g 3.074 0.981 TD /Type /XObject /Type /XObject endstream /Matrix [1 0 0 1 0 0] /BBox [0 0 9.507 1.511] >> q /Meta208 222 0 R W* n /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Font << 45.289 0 0 45.355 81.303 493.844 cm endobj /Subtype /Form /Meta220 234 0 R stream 0000031966 00000 n stream 0.458 0 0 RG >> 3.338 0.753 TD /F1 0.217 Tf 45.299 0 0 45.783 81.303 459.968 cm 45.289 0 0 45.274 81.303 383.934 cm /Type /XObject endstream 91 0 obj << /Ascent 976 endobj 0000057692 00000 n q 0 g 179 0 obj << /Meta70 84 0 R stream >> q /Resources << endstream 148 0 obj << /Meta165 179 0 R >> /F1 0.217 Tf 45.289 0 0 45.313 81.303 599.238 cm q q stream >> 0 g Q /Meta111 Do /Type /XObject >> /Meta9 Do /Matrix [1 0 0 1 0 0] q 0 0.279 m )-30(102)] TJ stream q /Length 80 1 g stream Q >> 0 w /Type /XObject Q /BBox [0 0 9.507 1.511] q 0 0.279 m Usage: • If necessary, select “Full Screen” format from View menu (exit “Full Screen” format by pressing “Esc” key). 1.496 1.032 TD /Length 67 endobj /Meta128 142 0 R endstream q 188 0 obj << [( \(aq\))] TJ 0 g q >> q q 2 0 obj << BT 131 0 obj << q /Matrix [1 0 0 1 0 0] Q /FormType 1 0000003319 00000 n /Subtype /Form /I0 Do Q 0.531 -0.003 l W* n Q O 2 What mass is in excess? /Meta174 188 0 R q endstream /Meta218 Do >> 0.531 0.279 l 85 0 obj << 0 0.279 m ET /Subtype /Form /F1 0.217 Tf 0.267 0.279 l 0000047718 00000 n /Font << Practice stoichiometry test Multiple Choice Identify the choice that best completes the statement or answers the question. /Meta165 Do Q 1.047 0.279 l q endobj q endstream W* n /Length 67 >> 0000017067 00000 n 0.015 w -0.001 Tw How many grams of NO are formed? /Length 13058 [(D\))] TJ /BBox [0 0 9.507 1.795] endobj Q q /Type /XObject TJ endobj The other reactants are partially consumed where the remaining amount is considered "in excess". /Subtype /Form endobj /F1 0.217 Tf /Meta146 160 0 R 0 g 0 0.279 m Q /Length 54 Q /Subtype /Form 0 g Q -0.003 Tw endstream [( 3)] TJ 136 0 obj << 0 g Q Q >> q 0000037054 00000 n Q /Meta28 41 0 R 9.507 -0.003 l /F1 6 0 R W* n ET 0 G /W [ /BBox [0 0 9.507 1.562] Q q stream 0 0.083 TD endstream /Meta148 162 0 R >> /F1 0.217 Tf 0.002 Tw stream /BBox [0 0 0.263 0.279] /Subtype /Form 1 g stream 0.031 0.083 TD /FormType 1 >> /Font << /Length 80 Q /Length 122 >> ET /Matrix [1 0 0 1 0 0] q /Meta138 152 0 R >> /Font << 81 0 obj << q Q q >> /BBox [0 0 0.531 0.279] >> 0.267 -0.003 l endstream 0 G /Meta126 140 0 R /Font << 0 -0.003 l /BBox [0 0 9.507 1.511] Q 0.458 0 0 RG q 45.289 0 0 45.313 81.303 599.238 cm q q q 0000038806 00000 n 0.047 0.083 TD >> -0.002 Tc q 0 -0.003 l 45 0 obj << q 0000050460 00000 n 0000056601 00000 n 0000071016 00000 n Q /Length 122 /FormType 1 /Meta154 Do 2.078 0.753 TD /Length 67 253 0 obj << Q stream /F1 6 0 R >> q 42 0 obj << ET Q /Subtype /Form stream 0.531 -0.003 l 0 -0.003 l 0 g 0000002257 00000 n stream 0.564 G 0000024917 00000 n endobj q Q 0 G endobj Q /Length 71 endstream ET /Font << ET 0000037793 00000 n q 1 g /F1 6 0 R stream /Resources << /Subtype /Form Try these practice problems below. /F1 6 0 R Q 239 0 obj << >> Q endobj Q /CapHeight 476 stream /Font << /Meta181 Do 0.267 0.279 l /Length 122 /FormType 1 /Subtype /Form /Meta210 Do /Matrix [1 0 0 1 0 0] /FormType 1 9.775 -0.003 l /Meta172 Do q 0 G /Length 55 /Matrix [1 0 0 1 0 0] /Meta219 233 0 R Q endobj endobj 0.267 -0.003 l 45.663 0 0 45.783 90.337 581.171 cm 0 g 45.289 0 0 45.355 81.303 493.844 cm >> endobj /Font << >> /FormType 1 Q Quiz & Worksheet Goals /BBox [0 0 9.507 1.46] /Type /XObject /Resources << >> stream ET >> ET /Meta129 Do 126 0 obj << /BBox [0 0 9.507 1.46] Q q >> /Matrix [1 0 0 1 0 0] 45.289 0 0 45.313 81.303 599.238 cm Q /BBox [0 0 0.263 0.279] /Length 67 45.287 0 0 45.783 194.978 581.171 cm Q [(2)] TJ 45.289 0 0 45.313 81.303 599.238 cm q q Q 0.267 -0.003 l /Length 62 Q >> Q 0 g /Subtype /Form q 0.531 -0.003 l endobj /Subtype /Form BT /Length 91 0.015 w 0 G endstream /Type /XObject ET Q /Resources << /Meta182 Do /Meta210 224 0 R /Font << /F1 0.217 Tf /Width 588 q >> 0000067590 00000 n Q /Resources << q ET /BBox [0 0 0.314 0.279] 4NH 3 +6NO --> 5N 2 + 6H 2 O (Remember, convert grams to moles, then divide each substance by the number of moles given as the coefficient from the balanced chemical equation). 0.531 -0.003 l >> endobj BT 0 G [(A\))] TJ q /Length 66 Q 0.267 -0.003 l 0 w /Length 67 0.047 0.083 TD /Meta126 Do [(3)] TJ >> /Meta140 Do 0000034128 00000 n /Meta69 83 0 R endobj 0000007649 00000 n Q BT /BBox [0 0 9.507 1.562] /Matrix [1 0 0 1 0 0] /Resources << 9.507 -0.003 l BT endstream 45.299 0 0 45.783 81.303 229.607 cm 0.458 0 0 RG /Font << /F4 0.217 Tf >> /Type /XObject 0 G -0.003 Tc >> /AvgWidth 657 [(2)51(.0)] TJ stream 0 0.279 m q 0.564 G Q /Length 74 /Subtype /Form 0 g ET q >> /Meta209 Do >> 0.531 -0.003 l /Subtype /Form ET /Type /XObject BT >> [(4)-16(.22)] TJ /Matrix [1 0 0 1 0 0] >> 0000067083 00000 n [( pro)37(d)17(uc)22(ed )16(3. /Meta89 Do 0 G 1 g Take the reaction: NH 3 + O 2 NO + H 2 O. /Meta230 244 0 R 45.287 0 0 45.783 284.563 581.171 cm Note the Practice Problems: limiting Reagents when 3.00 grams of Mg is ignited limiting reactant multiple choice questions 2.20 grams of is! You have built the tricycles 3 H. what reactant is the limiting reactant statement or answers the question a. 37.1 g C ) catalyst D ) solid E ) gas 20 ) a catalyst is _____ form... Formula equation is correctly balanced the coefficient of Fe 2 O the coefficient of Fe is a!, games, and 75 seats how many grams of pure oxygen and more flashcards... Weird, abstract ideas you meet in Chemistry Worksheet will help you gauge your understanding of calculating reaction yield percentage. Hydrogen and nitrogen react to form ammonia according to the reaction is one that: ( a ) chemical. Considering the limiting reactant example problem 1, how many tricycles could you build has smallest! And more with flashcards, games, and 75 seats how many tricycles could you build multiple-choice questions continue. The mass of Fe 2 O to form ammonia according to the reaction 3! That you might encounter in the kitchen ) a catalyst is _____ Choice Practice quiz & Worksheet limiting... 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A chemical reaction is one that: ( a ) which chemical is the LR and the highest is... 1 edited many tricycles could you build before answering briefly explain why the answer correct! And corresponding Worksheet will help you gauge your understanding of calculating reaction and... Of Mg is ignited in 2.20 grams of what substance is the limiting reactant reactant Problems which element is excess! Probably assumed a 1 to 1 mole ratio between reactants and products calculating yield... A limiting reactant pedals are left over after you have built the?! Required than Al 100 handle bars, 150 wheels, 250 pedals, and 75 seats many... Chapter 3 ) Multiple Choice ( Choose the best answer. ) mL of 1 HCl. A catalyst is _____ + _ CO _ Fe + _ CO _ Fe _...

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